A straight line l with negative slope passes through (8,2) and cuts the coordinate axes at P and Q. Find absolute minimum value of ''OP+OQ`` where O is the origin-

If a straight line L with negative slope passing through (8,1) meets the coordinate axes at A and B then minimum value of OA+OB is

A straight line L with negative slope passes through the point (8,2) and cuts positive co-ordinate axes at the points P and Q. Find the minimum value of OP+OQ as L varies where O is the origin.

A straight line L with negative slope passes through the point (8, 2) and cuts the positive co-ordinate axes at points P and Q. Find the absolute minimum value of OP + OQ, as L varies, where O is the origin.

A straight line L with negative slope passes through the point (8,2) and cuts the positive coordinate axes at points P and Q. Then the absolute minimum value of OP+OQ as L varies, [where O is the origin ] is 6n, then n=

A straight line with negative slope passing through the point (2,8) cuts the cordinate axes at A and B then minimum value of OA+OB (where 0 is origin) is equal to

A straight line with negative slope passing the point (1, 4) meets the coordinate axes at A and B. The minimum value of OA + OB =

A straight line with negative slope passing through the point (1,4) meets the coordinate axes at A and B.The minimum value of OA+OB is equal to

A straight line L with negative slope passes through the point (8,2) and cuts the positive coordinate axes at points P and Q. As L varies, the absolute minimum value of OP+OQ is (O is origin)