`I=int(dx)/((a+dx^2)sqrt(b-a x^2))`

I=int(dx)/((a+dx^(2))sqrt(b-ax^(2)))

(i) int (dx)/(x sqrt(x^2-1)) (ii) int (dx)/(x sqrt(ax -x^2))

Let I = int_1^2 (dx)/(sqrt(1 + x^2)), J = int_1^2 (dx)/(x) , then

" (i) "int(dx)/(sqrt(4-x^(2)))

If b>aI=int_(a)^(b)(dx)/(sqrt((x-a)(b-x))) then I

I=int(dx)/(sqrt(x^(2)-a^(2)))

If I=int(x^2+1dx)/(sqrt(1+x^(2))

(i) int_0^a sqrtx/(sqrtx+sqrt(a-x)) dx (ii) int_0^5 sqrtx/(sqrtx+sqrt(5-x)) dx (iii) int_0^a (dx)/(x+sqrt(a^2+x^2))

I=int(2)/(sqrt(x)-sqrt(x+7))dx

If I_(1) = int_(1)^(2)(dx)/(sqrt(1+x^(2))) and I_(2)= int_(1)^(2) (dx)/(x) then