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Theorem:- 3 There is one and only one ci...

Theorem:- 3 There is one and only one circle passing through three non collinear points and If two circles intersects in two points; then the line joining the centres is perpendicular bisector of common chords

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There is one and only circle passing through three non-collinear points.

There is one and only circle passing through three non-collinear points.

If two circles intersect in two points, prove that the line through the centres is the perpendicular bisector of the common chord.

If two circles intersect in two points,prove that the line through the centres is the perpendicular bisector of the common chord.

If two circles intersect in two points; prove that the line through the centres is the perpendicular bisector of the common chord.

Theorem 10.5 : There is one and only one circle passing through three given non-collinear points.

If two circles intersect at two points, then prove that their centres lie on the perpendicular bisector of the common chord.

If two circles intersect at two points, then prove that their centres lie on the perpendicular bisector of the common chord.

If two circles intersect at two points, then prove that their centres lie on the perpendicular bisector of the common chord.