`("lim")_(xvecoo)(a n-(1+n^2)/(1+n))=b ,` where `a` is a finite number, then `a=1` (b) `a=0` (c) `b=1` (d) `b=-1`

If lim_(n rarr oo)(an-(1+n^(2))/(1+n))=b,a finit number,then

The sum of first n odd natural numbers is 2n-1 (b) 2n+1 (c) n^2 (d) n^2-1

lim_(n rarr oo)(a^(n)+b^(n))/(a^(n)-b^(n)), where a

lim_(xrarr oo) (a^n_b^n)/(a^n-b^n) , where 1lt b lt a , is equal to

lim_(x rarr0)(1-cos(1-cos x))/(x^(n))=l a finite non- zero value then n=(a)1(b)2(c)3(d)4

If (lim_(x rarr0)({(a-n)nx-tan x}sin nx)/(x^(2))=0 where n is nonzero real number,the a is 0 (b) (n+1)/(n)( c) n(d)n+(1)/(n)