If center of a regular hexagon is at the origin and one of the vertices on the Argand diagram is `1+2i` , then its perimeter is `2sqrt(5)` b. `6sqrt(2)` c. `4sqrt(5)` d. `6sqrt(5)`

If centre of a regular hexagon is at origin and one of the vertices on Argand diagram is 1+2i, where i=sqrt(-1) , then its perimeter is

(sqrt(6)+sqrt(5)+ 1/(sqrt(6)+sqrt(5)))^2

Multiply: 6sqrt(5) and 2sqrt(5)

(2-sqrt(5))^(6)+(2+sqrt(5))^(6)=

6.The value of (sqrt(5)+sqrt(2))(sqrt(5)-sqrt(2)) is:

The centroid of an equilateral triangle is (0,0) If two vertices of the triangle lie on x+y=2sqrt(2), then one of them will have its coordinates.(a) (sqrt(2)+sqrt(6),sqrt(2)-sqrt(6))( b) (sqrt(2)+sqrt(3),sqrt(2)-sqrt(3))(c)(sqrt(2)+sqrt(5),sqrt(2)-sqrt(5))(d) none of these

If x=5+2sqrt(6), then (x-1)/(sqrt(x)) is equal to a.sqrt(2) b.sqrt(3)c.2sqrt(2)d.2sqrt(3)

(2sqrt(6))/(sqrt(2)+sqrt(3)+sqrt(5)) equals