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(cos 70^@)/(sin 20^@)+(cos 55^@ cosec 35...

`(cos 70^@)/(sin 20^@)+(cos 55^@ cosec 35^@)/(tan 5^@ tan 25^@ tan 45^@ tan 65^@ tan 85^@) `

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Prove that : (i) (sin 70^@)/(cos 20^@)+(cosec 20^@)/(sec 70^@)-2cos 70^@cosec 20^@=0 (ii) (cos 80^@)/(sin 10^@)+cos 59^@cosec 31^@=2 (iii) (2 sin 68^@)/(cos 22^@)-(2 cot 15^@)/(5 tan 75^@)-(3tan 45^@tan 20^@tan 40^@tan 50^@tan 70^@)/(5)=1 (iv) (sin 18^@)/(cos 72^@)+sqrt(3) (tan 10^@ tan 30^@tan 40^@tan 50^@tan 80^@)=2 (v) (7cos 55^@)/(3 sin 35^@)-(4(cos 70^@cosec 20^@))/(3(tan 5^@tan 25^@tan 45^@tan 65^@tan 856^@))=1

The value of tan 15^@ tan 25^@ tan 45^@ tan 65^@ tan 75^@ is

Evaluate the ((3 cos 43^(@))/(sin 47^(@)))^(2) - (cos 37^(@) "cosec" 53^(@))/(tan 5^(@) tan 25^(@) tan 45^(@) tan 65^(@) tan 85^(@))

Evaluate: (cos 58^@)/(sin 32^@)+(sin 22^@)/(cos 68^@)-(cos 38^@cosec 52^@)/(tan 18^@tan 35 ^@ tan 60^@tan 72^@tan 55^@) .

Without using the trigonometric tables, evaluate the following : (11)/(7) (sin 70^(@))/(cos 20^(@)) - (4)/(7) (cos 53^(@) "cosec" 37^(@))/(tan 15^(@) tan 35^(@) tan 55^(@) tan 75^(@))

Without using Trigonometric Tables evaluate the following :- (2cos67^@)/(sin23^@)-(tan40^@)/(cot50^@)-cos0^@+tan15^@tan25^@tan60^@tan65^@tan75^@ .

Evaluate : ( 1 ) cosec (65° +theta) -sec (25° - theta) - tan (55° + theta) + cot (35° - theta) (2) (3cos55^(@))/(7sin35^(@))-(4(cos70^(@)cosec20^(@)))/(7(tan5^(@)tan25^(@)tan45^(@)tan65^(@)tan85^(@)))