`cos x+cos3x+cos5x+cos7x=0`

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Find general solutions or solution as per given condition: cosx+cos3x+cos5x+cos7x=0

2cos x-cos3x-cos5x=

cos3x+cos2x+cos x=0

cos4x cos8x-cos5x cos9x=0 if

The fundamental period of (sin x+sin3x+sin5x+sin7x)/(cos x+cos3x+cos5x+cos7x) is (pi)/(k) then k=

cos9x cos7x = cos5x cos3x [-pi/4 le x le pi/4]

Prove the following: (frac(sinx-sin3x+sin5x-sin7x)(cosx-cos3x-cos5x+cos7x))=cot2x

Prove that (sinx+sin3x+sin5x+sin7x)/(cosx+cos3x+cos5x+cos7x)=tan4x

Lt_(x to 0) (cosx-cos4x)/(cos5x-cos7x)=

cos9x cos7x=cos5x cos3x; -pi/4 leq x leq pi/4