If z is not purely real then area bounded by curves `Img(z+1/z)=0` & `|z-1| = 2` is(in square units)-

If z is purely real; then arg(z)=0 or pi

Let "z" be a complex number,then the area bounded by the curve |z-5i|^(2) + |z-12|^(2) =169 in square units is

If (z+i)/(z+2i) is purely real then find the locus of z

If z is purely real and Re(z) < 0, then Arg(z) is

If w=alpha+ibeta, where beta!=0 and z!=1 , satisfies the condition that ((w- bar w z)/(1-z)) is a purely real, then the set of values of z is |z|=1,z!=2 (b) |z|=1a n dz!=1 (c) z=bar z (d) None of these

If w=alpha+i beta, where beta!=0 and z!=1 satisfies the condition that ((w-wz)/(1-z)) is a purely real,then the set of values of z is |z|=1,z!=2( b) |z|=1 and z!=1z=z(d) None of these

If w=alpha+ibeta, where beta!=0 and z!=1 , satisfies the condition that ((w- bar w z)/(1-z)) is a purely real, then the set of values of z is |z|=1,z!=2 (b) |z|=1a n dz!=1 (c) z=bar z (d) None of these

If w=alpha+ibeta, where beta!=0 and z!=1 , satisfies the condition that ((w- barw z)/(1-z)) is a purely real, then the set of values of z is |z|=1,z!=2 (b) |z|=1a n dz!=1 z= z (d) None of these

If w=alpha+ibeta, where beta!=0 and z!=1 , satisfies the condition that ((w- bar w z)/(1-z)) is a purely real, then the set of values of z is |z|=1,z!=2 (b) |z|=1a n dz!=1 (c) z=bar z (d) None of these

If z^4+1=sqrt(3)i (A) z^3 is purely real (B) z represents the vertices of a square of side 2^(1/4) (C) z^9 is purely imaginary (D) z represents the vertices of a square of side 2^(3/4)