The linear mass density of a rod of length 2L varies with distance (x) from center as `lambda=lambda_(0)(1+(x)/(L))` .The distance of COM from center is nL.Then n is

If linear charge density of a wire of length L depends on distance x from one end as lambda=(lambda_(0)(x))/(L .Find total charge of wire :-

The linear mass density of a thin rod AB of length L varies from A to B as lambda (x) =lambda_0 (1 + x/L) . Where x is the distance from A. If M is the mass of the rod then its moment of inertia about an axis passing through A and perpendicualr to the rod is :

Linear mass density of a rod AB ( of length 10 m) varied with distance x from its end A as lambda = lambda_0 x^3 ( lamda_0 is positive constant). Distance of centre of mass the rod, form end B is

the linear charge density of a thin metallic rod varies with the distance x from the end as lambda=lambda_(0)x^(2)(0 le x lel) The total charge on the rod is

The density of a thin rod of length l varies with the distance x from one end as rho=rho_0(x^2)/(l^2) . Find the position of centre of mass of rod.

[" A wire of length "L" is placed along "x" &axis "],[" with one end at the origin.The linear charge "],[" density of the wire varies with "],[" Q."" distance "x" from the origin as "lambda=lambda_(0)((x^(3))/(L))" ."],[" Where "varnothing_(0)" is a positive constant.The total "],[" charge "Q" on the rod is "]

A non uniform rod OM (of length l m) is kept along x-axis and rotating about an axis AB, which is perpendicular to rod as shown in the figure. The rod has linear mass densty that varies with the distance x from left end of the rod according to lamda=lamda_(0)((x^(3))/(L^(3))) Where unit of lamda_(0) is kg/m. What is the value of x so that moment of inertia of rod about axis AB (I_(AB)) is minimum?

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

A rod of length L is placed along the x-axis between x=0 and x=L . The linear mass density (mass/length) rho of the rod varies with the distance x from the origin as rho=a+bx . Here, a and b are constants. Find the position of centre of mass of this rod.