A particle of mass "m" is moving along a circular path of radius 'r' such that "l centripetal acceleration `a_(c)=k^(2)rt^(2)` .power delivered to the particles is: 1) `mk^(2)r^(2)t` 2) `2mk^(2)r^(2)t` 3) `1/2(mk^(2)r^(2)t` 4) Zero

A particle is moving along a circular path of radius of R such that radial acceleration of particle is proportional to t^(2) then

A Particle of mass 'M' moves in a uniform circular path of radius 'r' with a constant speed 'v' then its centripetal acceleration is .

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a_(c) is varying with time t as a_(c) = k^(2)rt^(2) , where k is a constant. The power delivered to the particle by the forces acting on it is :

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a_(c) is varying with the time t as a_(c)=k^(2)r^(3)t^(4) where k is a constant. The power delivered to the particle by the forces acting on it is

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is

A particle of mass 2kg start motion form rest on a circular path of radius r=4m with constant tangential acceleration 4 ms^(-2) . Find the net work done on the particle in initial 1 second.

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac is varying with time t as a_c = k^2rt^2 , where k is a constant. Calculate the power delivered to the particle by the force acting on it.