Normal form of `x+y+sqrt(2)=0` is

Normal form of the line x-y+sqrt(2)=0 is

Find the values of theta and p, if the equation x cos theta+y sin theta=p is the normal form of the line sqrt(3)x+y+2=0

Normal form of line x+y+1=0 is

Reduce each of the followringequations to normal form: (i)x+y-2=0 (ii) x+y+sqrt2=0 (iii)x+5=0 (iv)2y-3=0 (v)4x+3y-9=0

The equation of the normal to the curve y=sqrt(x-3) , which is parallel to the curve 6x+3y-4=0 are

Write the normal form of the equation of the plane 2x-3y+6z+14=0.

Find the slopes of the tangent and the normal to the curve y=sqrt(x) at x=9

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce the equation x+y-sqrt2=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)