The power of refrigerator,which freezes 100gm of water at 10C into ice at 0C in 100sec is

A refrigerator freezes 5 kg of water at 0^(@)C into ice at 0^(@)C in a time internal of 20 minutes. Assume that the room temperature is 20^(@)C . Calculate the minimum power needed to accomplish it.

A refrigerator converts 100 g of water at 25^(@)C into ice at -10^(@)C in one hour and 50 minutes. The quantity of heat removed per minute is (specific heat of ice = 0.5 "cal"//g^(@)C , latent heat of fusion = 80 "cal"//g )

Assertion : The power of a pump which raises 100 kg of water in 10 sec to a height of 100 m is 10 KW . Reason : The practical unit of power is horse power.

Four cubes of ice at -10^(@)C each one gm is taken out from the refrigerator and are put in 150 gm of water at 20^(@)C . The temperature of water when thermal equilibrium is attained. Assuming that no heat is lost to the outside and water equivalent of contaner is 46 gm . (Specific heat capacity of water = 1 cal//gm-^(@)C , Specific heat capacity of ice =0.5 cal//gm-^(@)C , Latent heat of fusion of ice = 80 cal//gm-^(@)C )