Let `theta=tan^(-1)((1)/(10))+tan^(-1)((1)/(9))+tan^(1)((1)/(8))+...+tan^(-1)(10)+tan^(-1)(11)` and `tan theta=(p)/(q)` where `p,q` are coprime then `p+q-6` is

If theta=tan^(-1)((1)/(10))+tan^(-1)((1)/(9))+...+tan^(-1)(1)+tan^(-1)(2)+...+tan^(-1)(10)+tan^(-1)(11) .If tan theta=(m)/(n) (where m,n are coprime) then the value of (m+n) is equal to

tan^-1 (1/(1+2))+tan^-1(1/(1+(2)(3)))tan^-1(1/(1+(3)(4)))+...tan^-1(1/(1+n(n+1)))=tan^-1 theta

tan^(-1)((1)/(1+1.2))+tan^(-1)((1)/(1)+2.3)+...+tan^(-1)((1)/(1+n(n+1)))=tan^(-1)theta then find the value of theta.

If theta = tan^(-1)(2/9) + tan^(-1) (4/33) + tan^(-1)(8/128) + tan^(-1)(16/513) +………. upton infty , then cot theta =

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

If P=(tan(3^(n+1)theta-tan theta)

If cos theta= (p-1)/(p+1) then tan theta=