if `A=(1,2),B=(3,-2) and P` moves in the plane such that `AP+BP=7` then the locus of `P` has two axes of symmetry. Their equations are

If A=(2, -3, 7), B = (-1, 4, -5) and P is a point on the line AB such that AP : BP = 3 : 2 then P has the coordinates

Two perpendicular tangents to the circle x^(2) + y^(2) = a^(2) meet at P. Then the locus of P has the equation

Two perpendicular tangents to the circle x^(2)+y^(2)=a^(2) meet at P. Then the locus of P has the equation

A(2,3),B(2,-3) are two points.The equation to the locus of P. such that PA+PB=8

A(2,3),B(-2,3) are two points.The locus of P which moves such that PA-PB=4

A(2,3) , B(-2,3) are two points.The locus of p which moves such that PA-PB=4 is

A(2 ,3) ,B(-1, 1) are two points.If P is a point such that /_APB=90^(@) and the locus of P is x^(2)+y^(2)-ax-by+1=0 then |a+b| is equal to

A(0,0),B(1,2) are two points.If a point P moves such that te area of Delta PAB is 2sq . units then the locus of P is

A(2,3),B(1,5),C(-1,2)" are three points.If "P" is a point moves such that "PA^(2)+PB^(2)=2PC^(2)" ,then the locus of "P" is "