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If for a sample of size 60, we have the following information `sumx_i^2=18000 \ and \ sumx_i^2=960` , then the variance is (a) 6.63 (b) 16 (c) 22 (d) 44

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Given that,
`sumx_i^2=18000 \ and \ sumx_i^2=960`
Required variance= `(sigma)^2=sum(x_i)^2/n - ((x_i)/2)^2`
`=1800/60-(960/60)^2`
...
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