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(cos20^@+8sin70^@.sin50^@.sin10^@)/sin^2...

`(cos20^@+8sin70^@.sin50^@.sin10^@)/sin^2(80)^@`

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(cos20^(@)+8sin10^(@)sin50^(@)sin70^(@))/(sin^(2)80^(@))=

(cos20^(0)+8sin70^(0)sin50^(@)sin10^(0))/(sin^(2)80^(@)) is equal to

(i) sin10^(@)sin50^(@)sin70^(@)

(cos 20^(@)+8 sin 70^(@) sin 50^(@) sin 10^(@))/( sin^(2)80^(@)) is equal to

sin10^(@)+sin20^(@)+sin40^(@)+sin50^(@)=sin70^(@)+sin80^(@)

sin10^(@)+sin20^(@)+sin40^(@)+sin50^(@)-sin70^(@)-sin80^(@)=

Show that: sn10^@+sin20^@+sin40^@+sin50^@=sin70^@+sin80^@

Prove that sin10^(@)+sin20^(@)+sin40^(@)+sin50^(@)=sin70^(@)+sin80^(@) .

Show that sin10^(@)+sin20^(@)+sin40^(@)+sin50^(@) =sin70^(@)+sin80^(@)