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The sum of the squares of deviation of 10 observations from their mean 50 is 250,then coefficient of variation is

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Given:
`bar X=50`
`n=10`
`(x_i-bar X)^2=250`
Therefore, `sqrt (variance of X) = sqrt frac{sum_(i=1)^(10) (x_i- bar X)^2}{n}=sqrt frac{250}{10}=5`
Using coefficient of variance`= frac{sigma}{X}xx 100`,
`frac{5}{50}xx100=10%`
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