If `z=[(sqrt(3)/2)+i/2]^5+[((sqrt(3))/2)-i/2]^5` , then `R e(z)=0` b. `I m(z)=0` c. `R e(z)>0` d. `R e(z)>0,I m(z)<0`

If z=((sqrt(3))/(2)+(1)/(2)i)^(5)+((sqrt(3))/(2)-(i)/(2))^(5), then (a) im(z)=0 (b) Re(z)>0,Im(z)>0(c)Re(z)>0,Im(z)<0 (d) Re(z)=3

If z=((sqrt(3))/(2)+(i)/(2))^(5)+((sqrt(3))/(2)-(i)/(2))^(5), then prove that Im(z)=0

If z=((sqrt(3))/(2)+(i)/(2))^(5)+((sqrt(3))/(2)-(i)/(2))^(5), then prove that Im(z)=0

If z=((sqrt(5))/(2)+(i)/(2))^(5)+((sqrt(5))/(2)-(i)/(2))^(5) , the prove that Im(z)=0 .

If z(2-i2sqrt(3))^(2)=i(sqrt(3)+i)^(4), then amplitude of z is

If z(2-2sqrt(3i))^(2)=i(sqrt(3)+i)^(4), then arg(z)=

If z = (-4 +2 sqrt3i)/(5 +sqrt3i) , then the value of arg(z) is

If z+sqrt(2)|z+1|+i=0, then z equals

Show that if iz^(3)+z^(2)-z+i=0, then |z|=1

If 8iz^(3)+12z^(2)-18z+27i=0, (where i=sqrt(-1)) then