The mean deviation of the numbers 3 ,4,5,6,7 from the mean is 5 ,(a) 2,(b) 5 (c) 1.2 (d) 0

Explanation

The mean of the given numbers us given as,

`bar X=frac{3+4+5+6+7}{5}=5`

Using `bar X`, we will find `abs(d_i)`.

`abs (d_i)=x_i-bar X`

So, using the `abs(d_i)` we will get `2` for `3`, `1` for `4`, `0` for `5`, `1` for `6`, and `2` for `7`.

Then, the mean deviation is,

`M.D=frac {sum abs(d_i)}{n}`

`=frac{2+1+0+1+2}{5}=1.2`