A batsman scores run in 10 innings as 38,70,48,34,42,55,63,46,54 and 44. The mean deviation about median is
`(a)8.6 `
` (b) 6.4 ` 
 ` (c) 10.6 ` 
`(d) 7.6`

Explanation

Arrange the values in ascending order,

`38, 42, 44, 46, 48, 54, 55, 70`

`N=10`

When `N` is even,
`Median=frac{(frac{N}{2})^(th) observation+((frac{N}{2}+1)^(th)observation)}{2}`

`Median=frac{5^(th) observation+(6^(th)observation)}{2}`

`Median=frac{(46+48)}{2}`

`Median=47`

`Mean` `deviation=frac{1}{N}sum_(i=1)^(N)abs(x_i-median)`
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