Solve `sqrt(3x^2-7x-30)+sqrt(2x^2-7x-5)=x+5.`

If sqrt(3x^(2)-7x -30) - sqrt(2x^(2) -7x -5) = x -5 has alpha and beta as its roots, then the value of alpha beta is

Solve sqrt(5x^(2)-6x+8)-sqrt(5x^(2)-6x-7)=1

Solve sqrt(2)x^(2)+7x+5sqrt(2)=0

Solve (i) sqrt(5x^(2)-6x+8)-sqrt(5x^(2)-6x-7)=1 (ii)Solve (x^(2)-5x+7)^(2)-(x-2)(x-3)=1

Solve : sqrt(2x+7)=x+2

Solve :sqrt(2x+7)+sqrt(3x-18)=sqrt(7x+1)