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[" (iv) "theta.2x+0.3y=1.3],[quad 0.4x+0...

[" (iv) "theta.2x+0.3y=1.3],[quad 0.4x+0.5y=2.3]

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[0.2x+0.3y=1.3],[0.4x+0.5y=2.3]

0.2x + 0.3y = 1.3,0.4x + 0.5y = 2.3

Solve each pair of equation by using the substitution method. 0.2x+0.3y=1.3 and 0.4x+0.5y=2.3.

Solve the following pair of linear equations by the substitution method: (iv)0.2x+0.3y=1.3 ,0.4x+0.5y=2.3

Solve the following pair of linear equations by the substitution method. 0.2x+0.3y=1.3 and 0.4 x+0.5y=2.3

Solve the pair of linear equations by the substitution method : 0.2x+0.3y=1.3 0.4x+0.5y=2.3

Solve the following pair of linear equations by the substitution method: 0.2x + 0.3y =1.3 0.4x + 0.5y= 2.3

Solve the following pair of linear equations by the substitution method: 0.2x+0.3y=1.3 0.4x+0.5y=2.3