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While calculating eh mean and variance of 10 readings, a student wrongly used the reading of 52 for the correct reading 25. He obtained the mean and variance as 45 and 16 respectively. Find the correct mean and the variance.

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Mean, `bar X=frac{sum x_i}{n}`
`45=frac{sum x_i}{10}`
`sum x_i=450`
corrected `sum x_i` `=450-52+25=423`
corrected `sum x_i` `=frac{423}{10}=42.3`
`sigma^2=16`
`sigma^2=frac{sum x_i^2}{n}-(frac{sum x_i}{n})^2`
`16=frac{sum x_i^2}{10}-(45)^2` ...
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