" (v) "t^(2)+1quad " (vi) "quad 7t^(4)+4t^(3)+3t-2

Classify the following polynomials as linear quadratic,cubic and biquadratic polynomials: 3y( ii) t^(2)+1 (iii) 7t^(4)+4t^(3)+3t-2

Differentiate w.r.t. time. (i) y=t^(2) " " (ii) x=t^(3//2)" " (iii) y=(1)/(sqrt(t)) (iv) x=4t^(3) " " (v) y=2sqrt(t) " " (vi) y=2t^(2)+t-1 (vii) y=3sqrt(t)+(2)/(sqrt(t)) (viii) y=t^(3)sin t " " (ix) x=te^(t) (x) x= sqrt(t)(1-t)

Subtract : 3t ^(4) - 4t ^(3) + 2t ^(2) - 6t + 6 from - 4t ^(4) + 8t ^(3) - 4t ^(2) - 2t + 11

Here are four descriptions of the position (in meters) of a puck as it moves in an xy plane: (1) x=-3t^(2)+4t-2andy=6t^(2)-4t (2) x=-3t^(3)-4t andy=-5t^(2)+6 (3) vecr=2t^(2)hati-(4t+3)hatj (4) vecr=(4t^(3)-2t)hati+hatj Are the x and y acceleration components constant? Is acceleration veca constant?

Statement :1 If a parabola y ^(2) = 4ax intersects a circle in three co-normal points then the circle also passes through the vertr of the parabola. Because Statement : 2 If the parabola intersects circle in four points t _(1), t_(2), t_(3) and t_(4) then t _(1) + t_(2) + t_(3) +t_(4) =0 and for co-normal points t _(1), t_(2) , t_(3) we have t_(1)+t_(2) +t_(3)=0.

Statement :1 If a parabola y ^(2) = 4ax intersects a circle in three co-normal points then the circle also passes through the vertex of the parabola. Because Statement : 2 If the parabola intersects circle in four points t _(1), t_(2), t_(3) and t_(4) then t _(1) + t_(2) + t_(3) +t_(4) =0 and for co-normal points t _(1), t_(2) , t_(3) we have t_(1)+t_(2) +t_(3)=0.

Classify the following polynomials as linear, quadratic, cubic and biquadratic polynomials: (i) 3y (ii) t^2+1 (iii) 7t^4+4t^3+3t-2

Let the function y = f(x) be given by x= t^(5) -5t^(3) -20t +7 and y= 4t^(3) -3t^(2) -18t + 3 where t in ( -2,2) then f'(x) at t = 1 is

Let the function y = f(x) be given by x= t^(5) -5t^(3) -20t +7 and y= 4t^(3) -3t^(2) -18t + 3 where t in ( -2,2) then f'(x) at t = 1 is

Which among the following relations is correct? (a) t_(3//4) = 2t_(1//2) (b) t_(3//4) = 3t_(1//2) (c) t_(3//4) = 1/2t_(1//2) (d) t_(3//4) = 1/3t_(1//2)