" (ii) "8x^(2)-22x-21=0

Solve each of the following equatins : x=8x^(2)-22x-21=0

Solve the following equatins for x: 8x^(2)-22x-21=0

Solve the following quadratic equation by the method of factorisation:(iv) 8x^2-22x-21=0

Solve for x by fractorisation 8x ^(2) - 22x - 21=0

Solve: 8x^(2)-22x-21=0 by the factorisation method.

Find the zeroes of the polynomial 8x^(2)-22x-21

Solve the following equation by the method of completing square : 8x^2+22x-21=0

Find the equations of tangents to the circle x^(2)+y^(2)-22x-4y+25=0 which are perpendicular to the line 5x+12y+8=0

(3,-4) is the point to which the origin is shifted and the transformed equation is X^(2)+Y^(2)=4 then the original equation is (A) x^(2)+y^(2)+6x+8y+21=0 (B) x^(2)+y^(2)+6x+8y-21,=0 (C) x^(2)+y^(2)-6x+8y+21=0 (D) x^(2)+y^(2)-6x-8y+21=0