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(g)quad 2^((3)/(10gs)x)=(1)/(64)...

(g)quad 2^((3)/(10gs)x)=(1)/(64)

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If 2^((3)/("log"_(3)x)) = (1)/(64) , then x =

If 2^((3)/("log"_(3)x)) = (1)/(64) , then x =

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (a) (19)/(64) (b) (64)/(19) (c) (27)/(16) (d) (-19)/(64)

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(16) (d) (-19)/(64)

Find the mean mu and variance sigma^2 for the following probability distribution : X: 0 1 2 3 P(X): 1/(64) (18)/(64) (18)/(64) (27)/(64)

(64)^((1)/(3))[(64)^((1)/(3))-(64)^((2)/(3))]=?

The value of 64^(-(1)/(3))(64^((1)/(3))-64^((2)/(3))), is 1 (b) (1)/(3)(c)-3(d)-2

((1)/(3))^(-10)*27^(-3)+((1)/(5))^(-4)*(25)^(-2)+(64^((1)/(9)))