A particle moves rectilinearly with a constant acceleration `1 m//s^2`. Its speed after `10` seconds is `5 m//s`. The distance covered by the particle in this duration is.

A particle is moving under a constant acceleration of 3m//s^(2) . The initial velocity of the particle is 10m/s. calculate the distance travelled by the particle is 5s and also in th 5th second of its motion.

A particle has an initial velocity of 9m//s due east and a constant acceleration of 2m//s^(2) due west. The distance coverd by the particle in the fifth second of its motion is :

A particle moving in one dimension with a constant acceleration of 2 m/s^(2) is observed to cover a distance of 5 m during a particular interval of 1 s. Thedistance covered by the particle in the next 1 s interval (in metre) is

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle moving with constant acceleration of 2m//s^(2) due west has an initial velocity of 9m/s due east. Find the distance covered in the fifth second of its motion.

A particle is moving in a straight line under constant acceleration of 4 m//s^(2) . If its velocity at t=0 is 10 m//s, the displacement of particle in the 5^(th) second of its motion is

A particle moving with constant acceleration of 2m/ s^(2) due west has an initial velocity of 9 m/s due east. Find the distace covered in the fifth second of its motion.