y=x^(sin2x)

Find the ratio of the two areas bounded by the curve y=x^2sin2x ( x being in radians) and the x-axis from x=0 from x=0 to x=pi .

x(dy)/(dx)-2y=x^(2)+sin(1)/(x^(2)),x>0

Solve the following linear differential equation (dy)/(dx)+(y)/(x log x)=(sin 2x)/(log x)

(dy)/(dx)+(3x^(2))/(1+x^(3))y=(sin^(2)x)/(1+x^(3))

If y=x^x-2^(sin x)" find " (dy)/(dx) .

Find the derivative of y = (sin x)/(x^2) with respect to x is

The derivative of y = (sin x)^(x^2) with respect to x is

If y=x^(2)sin(x^(3)) , then int ydx will be :