tan^(-1)*(log x)

If y=tan^(-1)[(logex)/(log (e/x))] + tan^(-1)[(8-logx)/(1+8 logx)] , then (d^(2)y)/(dx^(2)) is

If y=tan^(-1)[(logex)/(log (e/x))] + tan^(-1)[(8-logx)/(1+8 logx)] , then (d^(2)y)/(dx^(2)) is

Integration of 1/(1+((log)_e x)^2) with respect to (log)_e x is (tan^(-1)((log)_e x)/x)+C (b) tan^(-1)((log)_e x)+C (c) (tan^(-1)x)/x+C (d) none of these

Integration of (1)/(1+((log)_(e)x)^(2)) with respect to (log)_(e)x is ((tan^(-1)((log)_(e)x))/(x)+C(b)tan^(-1)((log)_(e)x)+C(c)(tan^(-1)x)/(x)+C(d) none of these

If y=tan ^(-1) ((log ( (e)/( x^(3))) )/( log ( ex^(3)) ) ),then (dy)/(dx) =

(d)/(dx)[(tan^(-1)(log((e)/(x^(2)))))/(log(ex^(2)))]=

Discuss the global maxima and global minima of f(x)=tan^(-1)x-(log)_e x in [1/(sqrt(3)),sqrt(3)]

y=tan^(-1)x+5log x-2e^(3x) then find (dy)/(dx)