Velocity `v` of a particle moving along x axis as a function of time is given by `v = 2t m//s`. Initially the particle is to the right of the origin and `2 m` away from it. Find the position (distance from origin) of the particle after first `3 s`.

Two particles move along x-axis in the same direction with uniform velocities 8 m//s and 4 m//s . Initially the first particle is 21 m to the left of the origin and the second one is 7 m to the right of the origin. The two particles meet from the origin at a distance of

[" Velocity of a particle moving along "x" -axis "],[" as a function of time is given as "v=(4-],[t^(2))m/s," where "t" is time in second.The "],[" displacement of particle during "t=0s" to "t],[=1s" is "]

A particle moves along x-axis with acceleration a=6(t-1) where t is in second. If the particle is initially at the origin and it moves along positive x-axis with v_(0)=2m//s , find the nature of motion of the particle.

v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Which of the following graph may be correct for the motion of particle

A particle moves along x- axis. It's velocity is a function of time according to relation V=(3t^(2)-18t+24)m//s assume at t=0 particle is at origin. Which of the following graph may be correct for the motion of particle

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

Consider the v-t diagram of a particle moving along x axis as shown below.Velocity is in m/s and time is in seconds

The acceleration of a particle moving along x-axis is given by a = 6t. Initially it has a velocity of 4m//s along negative x-direction and it is at the origin. When will it return to the origin (in sec.)?