[" 3.If "f=1cos n-sin x" o "],[[" since cosu "0],[0,0,1]]

If f(x)=[[cos x,-sin x,0],[sin x,cos x,0],[0,0,1]] , show that f(x).f(y)=f(x+y)

find the value for x F(x)=|[cos x,-sin x,0],[sin x,cos x,0],[0,0,1]|

Let f(x)= [[cos x, -sin x, 0],[sin x, cos x, 0],[0,0,1]] ,Show that f (x) f(y)= f(x+y) .

F(x) =[[cos x, -sin x, 0],[ sin x, cos x, 0],[ 0, 0, 1]] Show that F(x) F(y)=F(x+y)

If A= [[cos x,sin x,0],[-sin x,cos x,0],[0,0,1]]=f(x) then A^-1=

If F (x) = [[cos x,-sin x,0],[sin x, cos x, 0],[0,0,1], then show that F(x) F(y)= F (x+y).

If F(x) = [(cos x, - sin x, 0),(sin x, cos x, 0),(0,0,1)] and G(y) = [(cos y, 0, sin y),(0,1,0),(-sin y, 0, cos y)] then [F(x) G(y)]^(-1) is equal to a) F (-x) G(-y) b) G(-y) F(-x) c) F(x^(-1))G(y^(-1)) d) G(y^(-1))F(x^(-1))

if A=[[cos,sin x,0-sin x,cos x,00,0,1]]=f(x) then

Inverse of f(x) = [(cos x , sin x, 0),(-sin x, cos x, 0),(0,0,1)] is