7x^(2)+4x-21=0

The solution set of x^(2)-4x-21>=0 is

If (2a-5)x^(2)-4x-15=0 and (3a-8)x^(2)-5x-21=0} have equal root then

If two roots of x^(3)7x^(2)+4x+12=0 are in the ratio 1:3 then the roots are

Divide x^(2)-4x-21 by x-7

If (x^(2)+4x-21) is divided by x+7 , then the quotient is

For all x > 21, ((x^(2) + 8x + 7)(x - 3))/((x^(2) + 4x - 21)(x + 1)) = ?

Using remainder theorem, factorise : x^(3) + 7x^(2) - 21 x - 27 Completely and then solve x^(3) + 7x^(2) - 21 x - 27=0

Without solving, find the nature of the roots of the following equations: (i) 3x^(2)-7x+5=0 . (ii) 4x^(2)+4x+1=0 . (iii) 3x^(2)+7x+2=0 . (iv) x^(2)+px-q^(2)=0 .

Examine the nature of the roots of the equations (i) 2x^(2)+2x+3=0 (ii) 2x^(2)-7x+3=0 (iii) x^(2)_5x-2=0 (iv) 4x^(2)-4x+1=0

Which of the following equations has 2 as a root? (a) x^(2)-4x+5=0 , (b) x^(2)+3x-12=0 (c) 2x^(2)-7x+6=0 , (d) 3x^(2)-6x-2=0