(sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)=tan2 theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

If theta=7.5^(@) Find the value of quad sin8 theta*cos theta-sin6 theta cos3 thetacos2 theta*cos theta-sin3 theta*sin4 theta

(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

cos theta-cos3 theta+cos5 theta-cos7 theta=4sin theta sin4 theta cos2 theta

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

(sin theta+sin3 theta+sin5 theta)/(cos theta+cos3 theta+cos5 theta)=tan3 theta

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

(cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta