A particle executing harmonic motion is having velocities `v_1` and `v_2` at distances is `x_1` and `x_2` from the equilibrium position. The amplitude of the motion is

A particle executing linear S.H.M. has velocities v_(1) and v_(2) at distances x_(1) and x_(2) respectively from the mean position. The angular velocity of the particle is

A particle executing linear SHM has velocities v_(1) " and " v_(2) at dis"tan"ce x_(1) " and " x_(2) , respectively from the mean position. The angular velocity of the particle is

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance (2A)/3 from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion with amplitude A. Its speed is tripled at the instant that it is at a distance (2A)/3 from equilibrium position. The new amplitude of the motion is:

A particle performs simple harmonic motion wit amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is

A particle performs simple harmonic motion wit amplitude A. its speed is double at the instant when it is at distance (A)/(3) from equilibrium position. The new amplitude of the motion is

A particle executing S.H.M. has velocities v_1 and v_2 when at distances x_1 and x_2 from the centre of the path. Show that the time period given by