sin theta(-cos theta+1)/(sin theta+cos theta-1)=(1)/(sec theta-tan theta)

(sin theta-cos theta + 1) / (sin theta + cos theta-1) = sec theta + tan theta

If (sin theta-cos theta+1)/(sin theta+cos theta-1)=(x)/(tan theta-sec theta+1) then x=1)0 22 3tan theta-sec theta+14)tan theta+sec theta-1

(sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

The value of (sin theta+cos theta-1)/(sin theta -cos theta+1)xx(tan^2 theta(cosec^2 theta-1))/(sec theta-tan theta) is:

Find the value मान ज्ञात करें : (sin theta+cos theta-1)/(sin theta-cos theta+1)xx(tan^2 theta (cosec^2 theta -1))/(sec theta -tan theta )

Prove that (sin theta+cos theta)/(sin theta- cos theta) + (sin theta - cos theta)/(sin theta + cos theta) = ( 2sec^(2) theta)/(tan^(2) theta -1) .

Prove that (cos theta)/(1+sin theta)=(1-sin theta)/(cos theta)=sec theta-tan theta

(1/(cos theta)-1/(sin theta))+1/(cosec theta-cot theta)-1/(sec theta+tan theta) =?

Prove that: ((1)/(cos theta)-(1)/(sin theta))(1+(sin theta)/(cos theta)+(cos theta)/(sin theta))=sec theta tan theta-cosec theta cot theta