" If "(sin alpha)/(3)=(cos alpha)/(4)" then "3sin2 alpha+4cos2 alpha=

I : If (cos alpha )/(a)=(sin alpha )/(b) then a cos 2 alpha + b cos 2 alpha =a II : If (sin alpha )/(a) =(cos alpha )/(b) then a sin 2 alpha + b cos 2 alpha = a

If sin alpha/2 + cos alpha/2=1.4 , then: sin alpha cos alpha =

sin alpha-cos alpha=(1)/(3) then sin^(4)alpha-cos^(4)alpha=

if cos alpha + sin alpha = 3/4 , then sin ^6 alpha + cos ^6 alpha =

(sqrt2 - sin alpha - cos alpha )/( sin alpha - cos alpha)=

(sqrt2 - sin alpha - cos alpha )/( sin alpha - cos alpha)=

If cos alpha + sin alpha = (3)/(4) , then sin^(6) alpha + cos^(6) alpha is equal to

Calculate the value of (sin^(6)alpha +cos^(6) alpha + 3sin^(2) alpha cos^(2) alpha).

Prove that sin^(4) alpha + cos^(4) alpha + 2 sin^(2) alpha cos^(2) alpha = 1 .

If (cos3 alpha)/(cos alpha)=(1)/(3),0