Sum of the first `n` terms of the series `1/2+3/4+7/8+(15)/(16)+` is equal to (1988, 2M) `2^n-n-1` (b) `1-2^(-n)` `n+2^(-n)-1` (d) `2^n+1`

Sum of the first n terms of the series (1)/(2)+(3)/(4)+(7)/(8)+(15)/(16)+... is equal to (1988,2M)2^(n)-n-1(b)1^(6)-2^(-n)n+2^(-n)-1(d)2^(n)+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n+n-1 (b). n-1+2^(-n) (c). n+2^(-n)-1 (d). 2^n+1

Sum of the first n terms of the series 1/2+3/4+7/8+(15)/(16)+......... is equals to (a). 2^n-n-1 (b). 1-2^(-n) (c). n+2^(-n)-1 (d).None of these

Sum of the first n terms of the series (1)/(2)+(3)/(4)+(7)/(8)+(15)/(16)+... is equal to 2^(n)-n-1 b.1-2^(-n) c.n+2^(-n)-1 d.2^(n)+1