Home
Class 12
CHEMISTRY
From equation (i) and (ii), CO2hArrCO+...

From equation (i) and (ii),
`CO_2hArrCO+(1)/(2)O_(2)[K_(c1)=9.0xx10^(-12)` at `1000^(@)C]` (i)
`H_(2)OhArrH_(2)+(1)/(2)O_(2)[K_(c2)=7.0xx10^(-12)` at `1000^(@)C]` (ii)
the equilibrium for the reaction
`CO_(2)+H_(2)hArrCO+H_(2)O`
at the same temperature is

A

`0.78`

B

`2.0`

C

`16.2`

D

`1.28`

Text Solution

Verified by Experts

The correct Answer is:
D

(i) `CO_(2) hArr CO + 1/2O_(2) K_(1) = 9.1 xx 10^(-13)`
(ii) `H_(2)O hArr H_(2) + 1/2 O_(2)K_(2) = 7.1 xx 10^(-12)`
Object `CO_(2) + H_(2) hArr CO + H_(2)O`
equation (i) - (ii)
`:. K^(1) = (K_(1))/(K_(2)) = 1.28`
`C_(t) = C_(0)e^(-kt)`
`:. R = R_(0)e^(-kt)`
Promotional Banner

Topper's Solved these Questions

  • KVPY

    KVPY PREVIOUS YEAR|Exercise Mathematics|10 Videos
  • KVPY

    KVPY PREVIOUS YEAR|Exercise PART-I CHEMISTRY|35 Videos
  • KVPY 2021

    KVPY PREVIOUS YEAR|Exercise PART II CHEMISTRY|10 Videos

Similar Questions

Explore conceptually related problems

From equation (i) and (ii), CohArrCO+(1)/(2)O_(2)[K_(c1)=9.0xx10^(-12) at 1000^(@)C] (i) H_(2)OhArrH_(2)+(1)/(2)O_(2)[K_(c2)=7.0xx10^(-12) at 1000^(@)C] (ii) the equilibrium for the reaction CO_(2)+H_(2)hArrCO+H_(2)O at the same temperature is

Write the equilibrium constant of the reaction C(s)+H_(2)O(g)hArrCO(g)+H_(2)(g)

If 2H_(2)O_((g))hArr2H_(2(g))+O_(2(g)), K_(1)=2.0xx10^(-13) 2CO_(2(g))hArr2CO_((g))+O_(2(g)), K_(2)=7.2xx10^(-12) Find the equilibrium constant for the reaction CO_(2(g))+H_(2(g))hArrCO_((g))+H_(2)O_((g))

2H_(2)OhArrH_(3)O^(+)+OH^(-) K_(w)=1xx10^(-14) at 25^(@)C . Hence, K_(a) is:

If equilibrium constant of HA+H_(2)O hArr A^(-) +H_(3)O^(+) at 25^(@)C is 2.82 xx10^(-5) , then the equilibrium constant for HA + OH^(-) hArr A^(-) +H_(2)O at the same temperature is

The relation between K_(p) and K_(c) is K_(p)=K_(c)(RT)^(Deltan) unit of K_(p)=(atm)^(Deltan) , unit of K_(c)=(mol L^(-1))^(Deltan) The equilibrium constant of the following reactions at 400 K are given: 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g), K_(1)=3.0xx10^(-13) 2CO_(2)(g) hArr 2CO(g)+O_(2)(g), K_(2)=2xx10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g)+CO_(2)(g) hArr CO(g)+H_(2)O(g) is

The equilibrium constant for the following reactions at 1400 K are given. 2H_(2)O(g)hArr2H_(2)(g) + O_(2)(g) , K_(1)=2.1×x10^(-13) 2CO_(2)(g) hArr2CO(g)+O_(2)(g),K_(2) = 1.4 x× 10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g) + CO_(2)(g)hArrCO(g) + H_(2)O(g) is