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Diborane is formed the element as sho...

Diborane is formed the element as shown in equation (1)
`2B(s) + 3H_(2)(g) rarr 3B_(2)H_(6)(g)"…….."(1)`
Given that
`{:(H_(2)O(l)rarrH_(2)O(g),DeltaH_(1^(@))=44kJ),(2B(s)+3//2O_(2)(s)rarrB_(2)O_(3)(s),DeltaH_(2^(@))=-1273kJ),(B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g),DeltaH_(3^(@))=-2035 kJ),(H_(2)(g)+1//2O_(2)(g)rarrH_(2)O(l),DeltaH_(4^(@))=-286kJ):}`
the `DeltaH^(@)` for the reaction (1)` is -

A

`36 kJ`

B

`509 kJ`

C

`520 kJ`

D

`-3550 kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
(1) `{:(H_(2)O,rarr,H_(2)O,DeltaH=44kJ),((l),,(g),):}`
(2) `2B + 1/3 O_(2) rarr B_(2)O_(3) DeltaH = - 1273 kJ`
(3)`{:(B_(2)H_(6) + 3O_(2) rarr ,B_(2)O_(3) + 3H_(2)O),(,(g)),(,DeltaH=-2035kJ):}`
(4) `{:(H_(2)+1//2O_(2)rarr H_(2)O,DeltaH = - 286 kJ),((l),):}`
equation ` (2) + (4) xx 3 + (1) xx 3 - (3)`
`DeltaH = (-1273) + (-286) xx 3 + (44 ) xx 3 - (-2035) = 36 kJ`
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