After 2 hours the amount of a certain ra...

After 2 hours the amount of a certain radioactive substance reduces to `1//16^(th)` of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance is

A

15 min

B

30 min

C

45 min

D

60 min

Verified by Experts

The correct Answer is:

B

`(0.693)/(t_(1//2))=(2.303)/(2xx60)log. (a)/(a//16)`
`t_(1//2)=30 min`

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