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When the size of a spherical nanoparticl...

When the size of a spherical nanoparticle decreases from 30 nm to 10 nm, the ratio surface area/volume becomes

A

1//3 of the original

B

3 times the original

C

1/9 of the original

D

9 times the original

Text Solution

Verified by Experts

The correct Answer is:
B
`("Surface area")/("Volume")=(pid^(2))/((pid^(3))/6)=6/d`
`d_(1)=30 nm" "d_(2)=10 nm`
`((("Surface area")/("Volume"))_(2))/((("Surface area")/("Volume"))_(1))=(6/d_(2))/(6/d_(!))=d_(1)/d_(2)=30/10=3`
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