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Let A={ theta in R|cos^(2) (sin theta)+s...

Let `A={ theta in R|cos^(2) (sin theta)+sin^(2) (cos theta)=1}` and `B={ theta in R| cos (sin theta) sin (cos theta)=0}`. Then `A nn B`

A

is the empty set

B

has exactly one element

C

has more than one but finitely many elements

D

has infinitely many elements

Text Solution

Verified by Experts

The correct Answer is:
A
for `A nn B`
`cos (sin theta)=1` or `-1` & `sin (cos theta)=0`
Which is not possible
or `cos (sin theta)=0` & `sin (cos theta)=1` or `-1`
also not possible
so `A nn B` is an empty set
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