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In the figure AHKF, FKDE and HBCK are un...

In the figure AHKF, FKDE and HBCK are unit squares, AD and BF intersect in X. Then the ratio of the areas fo triangles AXF and ABF is-

A

1//4

B

1//5

C

1//6

D

1//8

Text Solution

Verified by Experts

The correct Answer is:
B

Equation of BF
y=2x
equation of AD x+2y=4
`x((4)/(5),(8)/(5))`
`(ar(DeltaAFX))/(ar(DeltaABF))=((1)/(2)xx1xx(2-(8)/(5)))/((1)/(2)xx1xx2)=(1)/(5)`
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