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The DeltaH for vaporization of a liquid ...

The `DeltaH` for vaporization of a liquid is 20kJ/mol. Assuming ideal behaviour, the change in internal energy for the vaporization of 1 mol of the liquid at `60^(@)C` and 1 bar is close to -

A

`13.2kJ//mol`

B

`17.2kJ//mol`

C

`19.5kJ//mol`

D

`20.0kJ//mol`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH=DeltaE+Deltan_(g)RT`
`20=DeltaE+8.314xx10^(-3)xx333`
`DeltaE=17.2kJ//mol`
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