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The radius of K^(+) is 133 pm and that o...

The radius of `K^(+)` is 133 pm and that of `Cl^-` is 181 pm. The volume of the unit cell of KCI expressed in `10^(-22) cm^(3)` is :

A

`0.31`

B

`1.21`

C

`2.48`

D

`6.28`

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(K^(+))+r_(CI^(-))=(a)/(2)`
`133+181=(a)/(2)`
a=2(133+181)
a=628pm
or `a=628xx10^(-10)cm`
and
volume =`a^(3)=(6.28xx10^(-8))^(3)cm^(3)`
`=2.4767xx10^(-22) cm^(2)`
`~~2.48xx10^(-22)m^(3)`
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