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Let ABCD be a square of side length 1...

Let ABCD be a square of side length 1, and `I^(-)` a circle passing through B and C, and touching AD. The readius of `I^(-)` is -

A

`(3)/(8) `

B

`(1) /(2)`

C

`(1)/(sqrt(2))`

D

`(5)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
D

Let O be centre of circle .
OM = radius =r
`therefore r^(2) (1-r)^(2) +((1)/(2))^(2)`

`implies 2r -1=(1)/(4) `
`implies 2r-1 =(1)/(4)`
` implies 2r =(5)/(4)`
`r=(5)/(8)`
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