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Let ABCD be a traezium with AD para...

Let ABCD be a traezium with AD parallel to BC. Assume there is a point M in the interior of the segement BC such that AB=AM and DC=DM . Then the ratio of the area of the tapezium to the area of triabgle AMD is -

A

2

B

3

C

4

D

Not determinable from data

Text Solution

Verified by Experts

The correct Answer is:
B

`("ar(ABCD)")/("ar(AMD)")=(3_(Delta)+3_(Delta 2))/(Delta_(1) +Delta_(2) )= (3)/(1)`
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