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The electronic configuration of an eleme...

The electronic configuration of an element with the largest difference between the `1^(st) and 2^(nd)` ionization energies is

A

`1s^(2)2s^(2)2p^(6)`

B

`1s^(2)2s^(2)2p^(6)3s^(1)`

C

`1s^(2)2s^(2)2p^(6)3s^(2)`

D

`1s^(2)2s^(2)2p^(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Na=1s^(2)2s^(2)2p^(6)3s^(1)`
`Na^(+)to1s^(2)2s^(2)2p^(6)[Ne]`
[Ne] is inert gas, so, electron removal is very diffucult so I.P. is very high.
`Na^(+)to1s^(2)2s^(2)2p^(5)`
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