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The molar conductivities of HCl, NaCl, C...

The molar conductivities of HCl, NaCl, `CH_(3)COOH`, and `CH_(3)COONa` at infinite dilution follow the order

A

`HClgtCH_(3)COOHgtNaClgtCH_(3)COONa`

B

`CH_(3)COONagtHClgtNaClgtCH_(3)COOH`

C

`HClgtNaClgtCH_(3)COOHgtCH_(3)COONa`

D

`CH_(3)COOHgtCH_(3)COONagtHClgtNaCl`

Text Solution

Verified by Experts

The correct Answer is:
A
Since conductance of `H^(+)` is highest so molar conductivity of HCl will be highest and after that conductance of `CH_(3)COOH` will come
`:."order"" " HClgtCH_(3)COOHgtNaClgtCH_(3)COONa`
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