The geometry and the number of unpaired electron (s) of `["MnBr"_(4)]^(2-)`, respectively, are

Options

A. tetrahedral and 1
B. square planar and 1
C. tetrahedral and 5
D. square planar and 5

Answer

C

Explanation

`["Mn Br"_(4)]^(-2)`
`x+(-1)4=-2`
`x=+2`
`Mn to 4s^(2)3d^(5)`
`Mn^(+2) to 4s^(@)3d^(5)`

We know that Br is weak field ligand so Hund's Rule is applicable

Hybridization is ` to sp^(3)`
and `N_(0)` of unpaired =5
electron.